My New Laptop

In a few weeks i'll finally have enough money to buy a fancy new laptop!

Features:

- Intel Core 2 Duo T9300 processor (6MB cache, 2.5MHz)
- 17" Ultrasharp screen, 1900x1200 resolution with truelife (glossy)
- 320GB SATA HDD
- 256MB Nvidia 8600 GeForce graphics card
- 3GB RAM
- All the software etc etc.
- $2200 from my bank account

Not to happy about the last part...

Once i've got my laptop I think i'll save up for a mean desktop!

The one good thing about about top of the line computers is that they are not even close to the cost of top of the line push bikes! So you really feel like your getting value for money.

Mark.

Falling Down the Rabbit Hole

Many people run at the very thought of quantum physics, personally I love it.

I've always been the type that likes to try and visualise what's going on around us. I was scanning over youtube the other day and found a neat series of short clips from 'Dr. Quantum', its an animated old man in a cape, who very successfully explains some very complicated quantum topics (A simple youtube search will find the clips for you).

I've messing around with XNA for a while now, and i'm at the point where I can begin working on my final year university project, a quantum astrophysics simulation engine. The idea is that the user will be able to scroll around a 3D model of our solar system, and place all sorts of cool astro-disasters. Ever wondered what would happen if our sun had enough mass to make a black hole?, what would happen to Earth if the moon hit us?

It will also attempt to simulate a theoretical quantum perspective (only 2 of the possible infitite time dimensions though)

XNA seems realitively straight forward compared to native DirectX, so the programming side (I hope) will not take more than a year. The physics side... well I think i'm going to need some help from our superstar ex-spacerocket-builder lecturer for that one.


Anyway, it should be interesting, whether its too ambitious, well time will tell.


Mark.

Whoops

Prove that sin(j*x) = j*(sinh(x)):

This is what I did:

sin(j*x) = (e^j*x - e^-j*x) / 2*j
j*(sinh(x)) = (e^x - e^-x) / 2

Therefore:

(e^j*x - e^-j*x) / 2*j = j*(e^x - e^-x) / 2

Whoops... If your not shaking your head already:

sin(j*x) = (e^jb - e^-jb) / 2j , where b = jx

sin(j*x) = (e^j*(j*x) - e^-j*(j*x)) / 2*j

sin(j*x) = (e^-x) - e^x)) / 2*j

sin(j*x) = ((e^-x) - e^x)) / 2*j ) * (j/j)

sin(j*x) = j*((e^-x - e^x)) / -2

sin(j*x) = j*(e^x) - e^-x)) / 2*j

-.-;